👤

Se considera punctele coliniare A,B,C in aceasta ordine si punctele M,N mijloacele segmentelor AB si BC . Daca AN=11 cm si MC = 10 cm , MN=?

Răspuns :

Notezi AM=MB=y
            BN=NC=X
Y+Y+X=11
2Y+X=11⇒X=11-2Y
Y+X+X=10
Y+2X=10
Y+2(11-2Y)=10
Y+22-4Y=10
22-10=4Y-Y
12=3Y
Y=4=MB
X=11-2*4
X=11-8
X=3=BN
MN=BM+BN
MN=3+4=7