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Calculati
((1+i)/(1-i))^11


Răspuns :

[tex] (\frac{1+i}{1-i})^{11} =( \frac{(1+i)^2}{(1-i)(1+i)})^{11}=( \frac{2i}{2})^{11}=i^{11}=i^4*i^4*i^3=-i [/tex]