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AJUTOR! Calculati:
radical din 2x+1 stiind ca x=1+3+3^2+3^3+...+3^2013
MULTUMESC!!!!


Răspuns :

Rezolvarea in atasament
Vezi imaginea SAOIRSE1
[tex]x=1+3+3^2+3^3+...+3^{2013} \\ x= \frac{3^{2013+1}-1}{3-1} \\ x= \frac{3^{2014}-1}{2} \\ \sqrt{2x+1}= \sqrt{\not2\cdot \frac{3^{2014}-1}{\not2}+1 }= \\ = \sqrt{3^{2014}-1+1}= \sqrt{3^{2014}}=3^{1007} [/tex]