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Doi frati au impreuna 210 nuci .Cate alune are fiecare baiat daca unul are 2 supra 5 din cantitatea celuilalt?

Răspuns :

x+y=210
x=(2/5)*y
(2/5)*y+y=210
((2/5)+1)*y=210
(7/5)*y=210
y=210*(5/7)=150
x=210-150=60