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CHIMIE
Se da o solutie cu md=40g ms =1000g se adauga peste ea o solutie de concentratie
40% si md 50 g .Aflati c3 md 3 si ms3


Răspuns :

C2=md2/ms2*100 => ms2=md2*100/C2 = 50*100/40 =125g

md3 = md1+md2 = 40+50=90g

ms3 = ms1+ms2 = 1000+125 = 1125g sol

C3=md3/ms3*100 = 90/1125*100 = Calculeaza !!