a)
a·b=880
a+b=442
Daca ai facut relatiile lui Viette, a+b=S=442, iar a·b=P=880
Conform relatiei atasate,
t²-St+P=0
t²-442S+880P=0
Δ = b²-4ac = 195364 - 3520 = 191844 = 438²
t1=x1=[tex] \frac{442+ \sqrt{438^{2} } }{2} [/tex] = [tex] \frac{442+438}{2} [/tex] = 880:2 = 440
t2=x2=[tex] \frac{442- \sqrt{438^{2} } }{2} [/tex] = [tex] \frac{442-438}{2} [/tex] = 4:2 = 2
Deci S: 440, 2
b) si c) se rezolva analog
