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Daca a=75, b+c=32,calculati: a+b+c=? 2a+b+c=?,3a+2b+2c=?

Răspuns :

a)[tex]a+b+c=75+32=107[/tex]
b)[tex]2a+b+c=2x75+32=150+32=182[/tex]
c)[tex]3a+2b+2c=2a+a+2b+2c=2*(a+b+c)+a=2*107+75=214+75=289[/tex]
a+b+c=75+32=107
2a+b+c=2x75+32=182
3a+2b+2c=3a+2(b+c)=3x75+2x32=225+64=289