[tex] \frac{^{3x)}1}{\;\;\;8}= \frac{3x}{24x}\;\\
\frac{^{4)}5}{\;\;\;6x}= \frac{20}{24x}\;\\
\frac{^{8)}7}{\;\;\;3x}= \frac{56}{24x} [/tex]
Obs.
se calculeaza numitorul comul ... [8;6x;3x]=...
8 = 2³
6x= 2*3*x
3x = 3*x
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[8;6x;3x]=2³*3*x = 24x
