👤

cati moli de H2SO4 sunt necesari pentru a reactiona cu 80 kg de NaOH ?

Răspuns :

2NaOH + H2SO4 --> Na2SO4 + 2H2O

MNaOH=ANa+AO+AH=23+16+1=40kg/kmol

n=m/M=80/40=2 kmoli NaOH

1 kmol =1000 moli
2 kmoli = 2000 moli 

2 moli NaOH...............1 mol H2SO4
2000 moli NaOH.........x moli H2SO4

x=1*2000/2=1000 moli H2SO4 = 1kmol H2SO4