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Se barboteaza 224 cm cubi acetilena de puritate 80% intr-o solutie de brom in tetraclorura de carbon de concentratie 3% obtinandu-se un compus tetrabromurat. Masa de solutie de apa de brom care poate fi decolarata este?

Răspuns :

p=Vp/Vimpur*100 => Vp=p*Vimp/100=80*224/100=179,2cm³ pur C2H2

n=V/Vm=179,2/22,4=8 mmoli C2H2

C2H2 + 2Br2 = C2H2Br4

1 mmol C2H2............2 mmoli Br2
8 mmoli C2H2..........x=16 mmoli Br2

m Br2=16*160=2560mg

C=md/ms*100 => ms=md*100/C=256000/3=85333,333mg=85,333g sol Br2