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cine stie urgentttt ...cu explicatii va rog ...x²-6x+5=0

Răspuns :

calculam discriminantul cu formula:
delta=b^2-4ac
a=1
b=-6
c=5
delta=36-20
delta=16

Calculam solutiile ecuatie folosind discriminantul:
x1,2=-b+ sau - √delta totul supra 2a

x1=(6+√16)/2
x1=(6+4)/2
x1=5

x2=(6-√16)/2
x2=(6-4)/2
x2=1

S={1;5}

Bafta!
[tex]\displaystyle x^2-6x+5=0 \\ \text{Ecuatie de grad 2 , aplicam delta si apoi formula} \ X_{1,2} \\ \\ \Delta=b^2-4ac \\ \Delta=(-6)^2-4\cdot1\cdot5 \\ \Delta=36-20 \\ \Delta=16 \\ \\ \boxed{X_{1,2}= \frac{-b\pm \sqrt{\Delta} }{2a} } \\ \\ \\ \\ X_1= \frac{6-4}{2}=1 \\ \\ X_2= \frac{6+4}{2}=5 \\ \\ S=\{1;5\} [/tex]