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daca a supra b este egal cu 3 supra 8 aflati valoarea raportului 9a-3b supra 2a+b

Răspuns :



[tex]\it \dfrac{a}{b}=\dfrac{3}{8} \Longrightarrow \dfrac{a}{3}=\dfrac{b}{8} = k \Longrightarrow a=3k,\ \ b=8k[/tex]

[tex]\it \dfrac{9a-3b}{2a+b}=\dfrac{9\cdot3k-3\cdot8k}{2\cdot3k+8k} = \dfrac{27k-24k}{6k+8k}=\dfrac{3k}{14k} =\dfrac{3}{14}.[/tex]