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a+2b+a×b=ab, aflati nr de forma ab,

Răspuns :

a+2b+a·b=ab
a+2b+a·b=10a+b
a+2b+a·b-10a-b=0
b-9a+a·b=0⇒b+a·b=9a⇒b(a+1)=9a
daca a=8 atunci b=8
daca a=2 atunci b=6
Deci numerele sunt:88,26.

a+2b+ab=10a+b
b+ab=10a-a
b(a+1)=9a

soluții:
a+1=9
a=8,
b=8

a+1=3
a=2
b=6