Răspuns :
53.5 g NH4Cl.........35.5 g Cl
10 kg NH4Cl..........x g Cl
x = 6.635 kg Cl
58.5 g NaCl.........35.5 g Cl
10 kg NaCl..........x g Cl
x = 6.068 kg Cl
111 g CaCl2.........2*35.5 g Cl
10 kg CaCl2..........x g Cl
x = 6.393 kg Cl
133.5 g AlCl3.........3*35.5 g Cl
10 kg AlCl3..........x g Cl
x = 7.977 kg Cl
10 kg NH4Cl..........x g Cl
x = 6.635 kg Cl
58.5 g NaCl.........35.5 g Cl
10 kg NaCl..........x g Cl
x = 6.068 kg Cl
111 g CaCl2.........2*35.5 g Cl
10 kg CaCl2..........x g Cl
x = 6.393 kg Cl
133.5 g AlCl3.........3*35.5 g Cl
10 kg AlCl3..........x g Cl
x = 7.977 kg Cl
a) MNH4Cl= AN + 4AH + ACl = 14 + 4*1 + 35,5 = 53,5kg/mol
mCl=35,5kg
53,5kg NH4Cl...........................35,5kg Cl
10kg NH4Cl.............................x=6,6355kg Cl
b) MNaCl = ANa + ACl = 23 + 35,5 = 58,5kg/kmol mCl=35,5kg
58,5 kg NaCl...........................35,5 kg Cl
10kg NaCl...............................x=6,0683kg Cl
c) MCaCl2 = ACa + 2ACl = 40 + 2*35,5 = 111kg/kmol
mCl=2ACl=2*35,5=71 kg Cl
111kg CaCl2..............................71kg Cl
10kg CaCl2...............................x=6,(396)kg Cl
d) MAlCl3 = AAl + 3ACl = 27 + 3*35,5= 133,5kg AlCl3
mCl=3ACl=3*35,5=106,5 kg Cl
133,5 kg AlCl3..........................106,5kg Cl
10kg..........................................x=7,97752kg Cl
M- masa moleculara
A- masa atomica
mCl=35,5kg
53,5kg NH4Cl...........................35,5kg Cl
10kg NH4Cl.............................x=6,6355kg Cl
b) MNaCl = ANa + ACl = 23 + 35,5 = 58,5kg/kmol mCl=35,5kg
58,5 kg NaCl...........................35,5 kg Cl
10kg NaCl...............................x=6,0683kg Cl
c) MCaCl2 = ACa + 2ACl = 40 + 2*35,5 = 111kg/kmol
mCl=2ACl=2*35,5=71 kg Cl
111kg CaCl2..............................71kg Cl
10kg CaCl2...............................x=6,(396)kg Cl
d) MAlCl3 = AAl + 3ACl = 27 + 3*35,5= 133,5kg AlCl3
mCl=3ACl=3*35,5=106,5 kg Cl
133,5 kg AlCl3..........................106,5kg Cl
10kg..........................................x=7,97752kg Cl
M- masa moleculara
A- masa atomica
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