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(4x+3)(4x-3)-(6x-1)+13=0
Va rog ajutatima sa rezolv aceasta ecuatie.


Răspuns :

(4x+3)(4x-3)-(6x-1)²+13=0
16x²-9-(36x²-12x+1)+13=0
16x²-9-36x²+12x-1+13=0
-20x²+12x+3=0
Δ=12²-4·(-20)·3
Δ=144+240
Δ=384=8√6
x₁=(-12-8√6)/(-40)=(-4)(3+2√6)/(-40)=(3+2√6)/10
x₂=(-12+8√6)/(-40)=(-4)(3-2√6)/(-40)=(3-2√6)/10