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Ştiind că tg (a/2)=1/sqrt(3), sa se calculeze sin a

Răspuns :

[tex]sina=\dfrac{2\cdot tg\dfrac{a}2}{1+tg^2\dfrac{a}2}=\dfrac{\dfrac2{\sqrt3}}{1+\left(\dfrac1{\sqrt3}\right)^2}=\dfrac{\dfrac2{\sqrt3}}{1+\dfrac1{3}}=\dfrac{2}{\sqrt3}\cdot\dfrac{3}4=\dfrac{\sqrt3}2.[/tex]

Green eyes.