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Cine imi poate explica de ce 

[tex] \sqrt{(0-6)^2+(8+0)^2} =10 [/tex]


Răspuns :

[tex] \sqrt{(0-6) ^{2}+(8+0)^{2}}= \\ \\ \sqrt{6^{2}+8^{2} } = \\ \\ \sqrt{36+64}= \\ \\ \sqrt{100} =10 \\ \\ \sqrt{(0-6) ^{2}+(8+0)^{2}}= 10[/tex]