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daca (x-3)la a 2 a=x la a doua +ax+9 atunci a este

Răspuns :

[tex](x-3)^2=x^2+ax+9\\ x^2-2x3+9=x^2+ax+9\\ *x^2-x^2;9-9=\ \textgreater \ 0(se~reduc)*\\ =\ \textgreater \ -6x=ax=\ \textgreater \ a=-6x:x=\ \textgreater \ a=-6\\\\ Proba:x^2-6x+9=x^2-6x+9 \sqrt{} [/tex]