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[tex] \sqrt{12^{2} +6^{2} [/tex] =?

Răspuns :

√144+36=√180=6√5
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[tex] \sqrt{12^{2} +6^{2} } = \sqrt{144+36} = \sqrt{180} = \sqrt{ 2^{2}*3^{2}*5}=6 \sqrt{5} [/tex]