a) 1) daca 3x-1<0 adica x<1/3 avem
|-3x-1-2|=8
3|x+1|=8
|x+1|=8/3 daca x<-1 => -x-1=8/3 => x=-1-8/3, x= -11/3<-1 e buna solutia
daca -1<x<1/3 => x+1=8/3 => x=5/3>1/3 nu e buna
2) daca x≥1/3
|3x+1-2|=8
|3x+1|=8
3x+1=8 (deoarece stim ca x≥1/3)
x=7/3 ≥1/3 e buna
deci x∈ {-11/3,1/3}
O zi buna!
