g.(3^2+2^3):(6^2-7×5)=(9+8):(36-35)=17:1=17
h.(4^3-23^0):3^2+2^2×8=(64-1):9+4×8=63:9+32=7+32=39
i. (2^2-3)^100+5:[3^2-4×(3^1-3^0)]×1^2013=(4-3)^100+5:[3^2-4×(3-1)]×1^2013=1^100+5:(3^2-4×2)×1^2013=1^100+5:(9-8)×1^2013=1^100+5:1×1^2013=1^100+5×1^2013=1^2113+5=6
j.21^2-2×{11^2+21:(2-1)+2×[1+2^3×(1+2)+2^4-2^1]}=21^2-2×[11^2+21:1+2×(1+2^3×3+2^4-2^1)]=21^2-2×[11^2+21:1+2×(1+8×3+2^3)]=2×[11^2+21:1+2×(1+8×3+8)]=2×[11^2+21:1+2×(1+24+8)]=2×(11^2+21:1+2×33)=2×(121+21+66)=2×(142+66)=2×208=416
Sper ca te-am ajutat!Coronița?