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500:a+(300:10-20)=60
(30×10)- (4×b+50×2)=100



Răspuns :

a)500:a+(300:10-20)=60
500:a+(30-20)=60
500:a+10=60|-10
500:a=50=>500:50
a=10
b)(30×10)-(4×b+50×2)=100
300-(4b+100)=100=>300-100
4b+100=200|+100
4b=300|:4
b=75



500:a+(30-20)=60
500:a+10=60
500:a=60-10
500:a=50
a=500:50
a=10



300-(4b+100)=100
4b+100=300-100=200
4b=200-100
4b=100
b=100:4
b=25