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cum determin factorul unei solutii de permanganat de potasiu de 0.1 n?

Răspuns :

1000mL sol. KMnO4 0.1N..............................0.1*Eg=0.1*31.6=3.16g 
Vt=Vr*F............................................................Vt=Vr*F
F=Vt/Vr

F=Vt/Vr=nr/nt

EgKMnO4=M/5=158/5=31.6g
MKMnO4=158g/mol