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65-{2x+[(x÷2+12)÷3+18]÷3}÷2=12

Răspuns :

65-{2x+[(x÷2+12)÷3+18]÷3}÷2=12
-{2x+[(x÷2+12)÷3+18]÷3}÷2=12 -65
{2x+[(x÷2+12)÷3+18]÷3}÷2=53
2x+[(x÷2+12)÷3+18]÷3=106
[(x÷2+12)÷3+18]÷3=106-2x
(x÷2+12)÷3+18=318-6x
(x÷2+12)÷3=318-6x-18
(x÷2+12)÷3=300-6x
(x÷2+12)=900-18x
x÷2=900-18x-12
x÷2=888-18x
x=1776-36x
37x=1776
x=48