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Se supun fierberii,in mediu acid,200 ml solutie de glucoza 2M cu 200 ml solutie de zahar 3M. Molaritatea glucozei in solutia finala va fi?

Răspuns :

Cm1=n1/Vs1==>n1=Cm1*Vs1=2*0.2=0.4 moli

Cm2=n2/Vs2==>n2=0.2*3=0.6 moli

nt=0.4+0.6=1 mol

Vsf=200+200=400ml=0.4L

Cmf=nt/Vsf=1/0.4=2.5 moli/L