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am nevoie de rezolvare.[tex] \int \frac{ x^{2} }{x+1} dx [/tex]

Răspuns :

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(x²-1+1)/(x+1)=(x²-1)/(x+1+1/(x+1)=  x-1+1/(x+1)
Integrezi
∫(x-1+1/(x+1)]dx=∫xdx-∫dx+∫dx/(x+1)=x²/2-x+ln(x+1)+C