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determinati compozitia procentuala a substantei FeO











Răspuns :

M(masa moleculara)FeO=
=A Fe+A O
=56+16
=72
72gFeO...56gFe...16gO
100gFeO.....x.......y
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=> x=100•56/72
=5600/72
=77,7%Fe
y=16•100/72
=1600/72
=22,2%O