[tex]1. (3x+1)^2=4\\
9x^2+6x+1=4\\
9x^2+6x-3=0\\
3x^2+2x-1=0\\
3x^2+3x-x-1=0\\
3x(x+1)-(x+1)=0\\
(3x-1)(x+1)=0\\
i)3x-1=0\Rightarrow x=\frac{1}{3} \notin Z\\
ii)x+1=0\Rightarrow x=-1 \in Z[/tex]
[tex]2.x=pretul\ initial\\
x+\frac{10}{100}*x-\frac{15}{100}(x+\frac{10}{100}*x})=561\\
\frac{110x}{100}-\frac{15}{100}\cdot \frac{110x}{100}=561\\
\frac{110x}{100}-\frac{1650x}{10000}=561|\cdot 10000\\
11000x-1650x=5610000\\
9350x=5610000\\
x=600 lei[/tex]