M, CuS04x5H2O= (64gCu+32gS+4x16gO)+(5gHx18gO)
= 160gCuSo4 +90gH2O===> 250g
deci in 250g cristalohidrat se gaseste 160g sare anhidra si 90g apa
5g.............................................m=3,2g.....................1,8g
CONCENTRATIILE SOLUTIILOR SE EXPRIMA IN FUNCTIE DE SAREA ANHIDRA iar apa pe care o contine se adauga apei ce trebuie adaugata la prepararea solutiei
c/100= md/ms, unde ms= md+m,apa
8/100= 3,2/ms---> ms= 40g---> m,apa= ms-md= 40-3,2=> 36,8g
m,apa= 36,8- 1,8=> 35g apa