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Cum se calculeaza [tex]e^{ x^{2}+2x } +e ^{-x} [/tex] derivat ?


Răspuns :

f'(x)=(eˣ²⁺²ˣ+e⁻ˣ)'=((2*x+3)*e⁽ˣ⁽ˣ⁺³⁾⁺ˣ⁾-eˣ*(e⁽ˣ⁽ˣ⁺³⁾⁾+1)/e²ˣ=
=
(2*x+3)*e⁽ˣ⁽ˣ⁺³⁾⁻ˣ⁾-(e⁽ˣ⁽ˣ⁺³⁾⁾+1)/eˣ=(2*(x+1)*e⁽ˣ⁽ˣ⁺³⁾⁾-1)/eˣ