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Rezolvati ecuatia (x-3)²-(x-8)²=(√2x+1)²-2x²-10,in multimea numerelor reale

Răspuns :

x^2 - 6×+9 -×^2 +16×-64 = 2×^2 + 2rad2x + 1 -2x^2-10
-6×+16×+9-64 = 2rad2x + 1 -10
-6×+16× + 2rad2x = -9+64-1+10
10× + 2rad2x = 55+9
10× + 2rad2x = 64