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de descompus in factori daca e posibil,expresia:
x²-10x+21
6x²-11x+3
3x²+7x-6


Răspuns :

x²-10x+21 = x²-7x-3x+21=x(x-7)-3(x-7)=(x-7)(x-3)
6x²-11x+3 = 6x²-2x-9x+3=2x(3x-1)-3(3x-1)=(3x-1)(2x-3)
3x²+7x-6= 3x²+9x-2x-6=x(3x-2)+3(3x-2) =(3x-2)(x+3)