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VA ROG AJUTATI-MA!!!
Aratati ca 9•2048^183+16•27^671 < 5^2015


Răspuns :

3^2x(2^11)^183+2^4x(3^3)^671=3^2x2^2013+2^4x3^2013=3^2x2x2^(1006x2)+2^4x3x3^(1006x2)
5^2015=5^3x5^(1006x2)=>
simplificam exponentii cu 1006
avem: 3^2x2^3+2^4x3^3=72+432=504<5^5