Formula moleculara este [tex] C_{n}H_{2n+2}O_{n} [/tex]
Masa moleculara: M=12n+2n+2+16n=30n+2
(30n+2)g alcool................................16n grame oxigen
100...................................................52,17
(30n+2)52,17=1600n
1565,1n+104,34=1600n
104,34=34,9n
n=3
Adica [tex] C_{3}H_{8}O_{3} \\
sau C_{3}H_{5}(OH)_{3} [/tex]
