100g otel...............0,02g C
1g otel.....................x g C
-----------------------------------------
x=[tex] \frac{1*0,02}{10} [/tex]
x=0,002g C
MC=masa unui mol de carbon=12g\mol
Masa molara CO2= Ac+2Ao
MCO2 =12+16*2
MCO2=44g\mol
C+O2=CO2
12gC.................44gCO2
2gC................... y g CO2
--------------------------------------
y=[tex] \frac{2*44}{12} [/tex]
y=[tex] \frac{88}{12} [/tex]
y=7,33gCO2
Moli=[tex] \frac{7,33}{44} [/tex] =0,167 moli (CO2)
Sper ca te-am ajutat!
