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sa se inparta nr 18 in parti i.p cu nr 3,6,9

Răspuns :

k/3+k/6+k/9=18
(12k+6k+4k)18=18
22k=648
k=648/22=324/11
k/3=(324/11)/3=108/11=9,(81)
k/6=(324/11)/6=54/11=4,(90)
k/9=(324/11)/9=36/11=3,(27)

(x;y;z) i.p. (3;6;9) ..................
Vezi imaginea ALITTA