Răspuns:
Explicație pas cu pas:
2a/3 = 3b/5 = 5c/4 = k → coeficient de proportionalitate
2a/3 = k ⇒ a = 3 k/2
3b/5 = k ⇒ b = 5 k/3
5 c /4 = k ⇒ c = 4 k/5
_________________
a + b + c = 119
3k/2 + 5k/3 + 4 k/5 = 119 [ × 30, ptr. ca cmmmc al numitorilor=2×3×5=60
45 k + 50 k + 24 k = 119 × 30
119 k = 119 × 30 [ : 119
k = 30
___________________________
a = 3k/2 = (3×30)/2 = > a = 45
b = 5k/3 = (5×30)/2 => b = 50
c = 4k/5 = (4×30)/5 => c = 24
