1.calculez masa de acid ce reactioneaza cu 15gZn;
A=65g/molZn ,M= (1gH +35,5gCl)/mol --> 36,5g/mol HCl
ECUATIA reactiei:
1mol 2mol
Zn + 2HCl= ZnCl2 + H2
65g 2x36,5g
15g m= 15x73/65=16,85g HCl
2.masa obtinuta reprezinta masa de acid dizolvata ,md,in solutia data
din relatia, c/100= md/ms, calculez masa solutiei:
---> 25/100= 16,85/ ms
ms=100x16,85/25 calculeaza ms, in g!!!!!!