👤

Cat fac [tex] \sqrt{72} + \sqrt{98} -2 \sqrt{128} [/tex] ?

Răspuns :

[tex]\sqrt{72}+\sqrt{98}-2\sqrt{128}=\\ 6\sqrt{2}+7\sqrt{2}-2*8\sqrt{2}=\\ 13\sqrt{2}-16\sqrt2=-3\sqrt2[/tex]
6√2+7√2-2x8√2=6√2+7√2-16√2=(6+7-16)√2=-3√2 sper ca te-am ajutat si bafta la scoala! :)