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suma a 5 numere naturale pare consecutive este 40. aflati numerele. REPEDE !VA ROG !

Răspuns :

a+a+2+a+4+a+6+a+8=40
5a+20=40
5a=40-20
5a=20
a=20:5
a=4

a+2=4+2=6
a+4=4+4=8
a+6=4+6=10
a+8=4+8=12

a+b+c+d+e=40
a,b,c,d,e=nr pare
b=a+2
c=a+4
d=a+6
e=a+8
a+a+a+a+a+2+4+6+8=40
5a+20=40
5a=20
a=4
b=6
c=8
d=10
e=12