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2x+1supra 4x^2+5x +1 (o fractie ) +2x supra 4x^2+5x+1
Cum fac sa obtin 1supra x+1
Va roggggg.....


Răspuns :

   
[tex]\displaystyle \\ \frac{2x+1}{4x^2+5x +1} +\frac{2x}{4x^2+5x +1} = \\ \\ = \frac{2x+1+2x}{4x^2+5x +1} =\\ \\ = \frac{4x+1}{4x^2+4x + x +1} = \\ \\ =\frac{4x+1}{4x(x+1) + (x +1)} = \frac{(4x+1}{(x+1)(4x + 1)} = \boxed{\frac{1}{x+1}} [/tex]